In calculus 1, students are taught about the definition of a derivative, f ′ ( x ) = f ( x + h ) − f ( x ) h f'(x)=\frac{f(x+h)-f(x)}{h} f ′ ( x ) = h f ( x + h ) − f ( x ) , which is used to generically define the derivative of a function f f f . This definition is useful because it is able to differentiate any function f f f at any point x x x , but in certain situations also simplifies nicely for all points x x x ; this is a collection of those functions.
Simple Rules¶
d d x [ c ] = 0 \frac{d}{dx}[c]=0 d x d [ c ] = 0
d d x [ x ] = 1 \frac{d}{dx}[x]=1 d x d [ x ] = 1
d d x [ c ∗ f ( x ) ] = c ∗ d d x [ f ( x ) ] \frac{d}{dx}[c*f(x)]=c*\frac{d}{dx}[f(x)] d x d [ c ∗ f ( x )] = c ∗ d x d [ f ( x )]
d d x [ f ( x ) + g ( x ) ] = d d x [ f ( x ) ] + d d x [ g ( x ) ] \frac{d}{dx}[f(x)+g(x)]=\frac{d}{dx}[f(x)]+\frac{d}{dx}[g(x)] d x d [ f ( x ) + g ( x )] = d x d [ f ( x )] + d x d [ g ( x )]
Power Rule¶
d d x [ x n ] = n x ( n − 1 ) \frac{d}{dx}[x^n]=nx^{(n-1)} d x d [ x n ] = n x ( n − 1 )
Product Rule¶
d d x [ f ( x ) g ( x ) ] = f ′ ( x ) g ( x ) + f ( x ) g ′ ( x ) \frac{d}{dx}[f(x)g(x)]=f'(x)g(x)+f(x)g'(x) d x d [ f ( x ) g ( x )] = f ′ ( x ) g ( x ) + f ( x ) g ′ ( x )
Quotient Rule¶
d d x [ f ( x ) g ( x ) ] = f ′ ( x ) g ( x ) − f ( x ) g ′ ( x ) g ( x ) 2 \frac{d}{dx}\left[ \frac{f(x)}{g(x)} \right]=\frac{f'(x)g(x)-f(x)g'(x)}{g(x)^2} d x d [ g ( x ) f ( x ) ] = g ( x ) 2 f ′ ( x ) g ( x ) − f ( x ) g ′ ( x )
Chain Rule¶
d d x [ f ( g ( x ) ) ] = f ′ ( g ( x ) ) ∗ g ′ ( x ) \frac{d}{dx}[f(g(x))]=f'(g(x))*g'(x) d x d [ f ( g ( x ))] = f ′ ( g ( x )) ∗ g ′ ( x )
Natural Number (e) Rules¶
d d x [ e x ] = e x \frac{d}{dx}[e^x]=e^x d x d [ e x ] = e x
d d x [ e c x ] = c e c x \frac{d}{dx}[e^{cx}]=ce^{cx} d x d [ e c x ] = c e c x
d d x [ ln ( x ) ] = 1 x \frac{d}{dx}[\ln(x)]=\frac{1}{x} d x d [ ln ( x )] = x 1
L’Hopital’s Rule¶
If lim x → a f ( x ) \lim_{ x \to a } f(x) lim x → a f ( x ) and lim x → a g ( x ) \lim_{ x \to a } g(x) lim x → a g ( x ) both approach 0 0 0 or both approach ± ∞ \pm\infty ± ∞ , then:
lim x → a f ( x ) g ( x ) = lim x → a f ′ ( x ) g ′ ( x ) \lim_{ x \to a } \frac{f(x)}{g(x)}=\lim_{ x \to a }\frac{f'(x)}{g'(x)} lim x → a g ( x ) f ( x ) = lim x → a g ′ ( x ) f ′ ( x )
Trigonometric Functions¶
d d x [ sin ( x ) ] = cos ( x ) \frac{d}{dx}[\sin (x)]=\cos(x) d x d [ sin ( x )] = cos ( x )
d d x [ cos ( x ) ] = − sin ( x ) \frac{d}{dx}[\cos(x)]=-\sin(x) d x d [ cos ( x )] = − sin ( x )
d d x [ tan ( x ) ] = sec 2 ( x ) \frac{d}{dx}[\tan(x)]=\sec^2(x) d x d [ tan ( x )] = sec 2 ( x )
d d x [ sec ( x ) ] = sec ( x ) ∗ tan ( x ) \frac{d}{dx}[\sec(x)]=\sec (x)*\tan(x) d x d [ sec ( x )] = sec ( x ) ∗ tan ( x )
d d x [ csc ( x ) ] = − csc ( x ) ∗ cot ( x ) \frac{d}{dx}[\csc(x)]=-\csc(x)*\cot(x) d x d [ csc ( x )] = − csc ( x ) ∗ cot ( x )
d d x [ cot ( x ) ] = − csc 2 ( x ) \frac{d}{dx}[\cot(x)]=-\csc^2(x) d x d [ cot ( x )] = − csc 2 ( x )
Inverse Trigonometric Functions¶
d d x [ sin − 1 ( x ) ] = 1 1 − x 2 \frac{d}{dx}[\sin^{-1}(x)]=\frac{1}{\sqrt{ 1-x^2 }} d x d [ sin − 1 ( x )] = 1 − x 2 1
d d x [ cos − 1 ( x ) ] = − 1 1 − x 2 \frac{d}{dx}[\cos^{-1}(x)]=-\frac{1}{\sqrt{ 1-x^2 }} d x d [ cos − 1 ( x )] = − 1 − x 2 1
d d x [ tan − 1 ( x ) ] = 1 1 + x 2 \frac{d}{dx}[\tan^{-1}(x)]=\frac{1}{1+x^2} d x d [ tan − 1 ( x )] = 1 + x 2 1
d d x [ csc − 1 ( x ) ] = − 1 x x 2 − 1 \frac{d}{dx}[\csc^{-1}(x)]=-\frac{1}{x\sqrt{ x^2-1 }} d x d [ csc − 1 ( x )] = − x x 2 − 1 1
d d x [ sec − 1 ( x ) ] = 1 x x 2 − 1 \frac{d}{dx}[\sec^{-1}(x)]=\frac{1}{x \sqrt{ x^2-1 } } d x d [ sec − 1 ( x )] = x x 2 − 1 1
d d x [ cot − 1 ( x ) ] = − 1 1 + x 2 \frac{d}{dx}[\cot^{-1}(x)]=-\frac{1}{1+x^2} d x d [ cot − 1 ( x )] = − 1 + x 2 1